Re: php side code for jQuery

From: Date: Mon, 19 May 2014 20:30:52 +0000
Subject: Re: php side code for jQuery
References: 1  Groups: php.general 
Request: Send a blank email to php-general+get-323345@lists.php.net to get a copy of this message
You could either send information about which function you would like to call on the url parameter ($_GET) $.ajax('myserver.php?function=ajaxRetrieveData'); or adding into data object ($_GET or $_POST) : $.ajax({ type: "POST", url: "myserver.php", data: { function: 'ajaxRetrieveData' } }); and then using a router to find the function myserver.php $function = $_POST['function']; $object->$function(); Please, do not use this code without properly validation. 2014-05-19 17:21 GMT-03:00 ICCSI <inungh@gmail.com>: > I use following code for jQuery.ajax to call php. > > $.ajax('myserver.php") > > It seems that one php file only work for one jquery ajax code, > Is it possible to have more than one function or one return different > result in one php file? > > Your information and help is great appreciated, > > Regards, > > > Iccsi, -- Att, ____________________________________________________ Ricardo R Bonfim

« previous php.general (#323345) next »