Re: socket gives notice on server side(simple newbie code)

From:	Jim Giner	Date:	Wed, 20 Aug 2014 15:09:52 +0000
Subject:	Re: socket gives notice on server side(simple newbie code)
References:	1 2 3	Groups:	php.general
Request:	Send a blank email to php-general+get-323752@lists.php.net to get a copy of this message

On 8/20/2014 11:00 AM, Negin Nickparsa wrote:

echo "you entered ".$input; if($stock[$input]!=NULL) {
     $answer=$stock[$input];
     socket_write($sock,$answer, $port);
} else{
     echo socket_strerror(0);
}

How about adding the following before the above lines: if (!isset($stock[$input])) print_r($stock);