Re: How to keep $_POST value when I have 3 submit options?

On Oct 23, 2014, at 10:10 AM, Negin Nickparsa wrote:

I have items showing up in list view or grid view. I have 2 buttons List and Grid and Items will show up in Grid view and List view also I order them in a select tag by price and other options when I sort by name I want to remember the state of view whether it is grid or if it is list user selects Grid view and then wants to order them by price. but when they order by price booom!(submitted) they will go to default view which was List view.It is not correct so bad.

How does the user designate the view he wants to see? It appears that there must be a way, via javascript ajax call* , to tell the server initially what the preferred view is, so when the page reloads the correct view is displayed. *or get/post sent to the page that is being viewed. I would do this as <?php // in the top of the page being viewed. $_file_self = basename($_SERVER['PHP_SELF']); $_view = ''; if($_GET['view']) { $_view = $_GET['view']; } ?> The <a href="<?php print $_file_self ?>?view=grid">Grid View</a> <a href="<?php print $_file_self ?>?view=list">List View</a> You may also want to save the view preference as a session variable or have code write a preference file for the user. Is the user required to have an account? If so, include a variable that designates the default view preference.

I have an event onchange that when I click on selection the form will be submitted I want to keep the values so that it can remember whether it should sort the items in grid view or list view the live example can be seen here: http://www.lenmar.com/general-purpose/aa/aa/nickel-metal-hydride/nickel-metal-hydride-battery this is the older version which is working with Get method but the test server is with $_POST I am showing the concept to help clarifying the problem as far as I attempted, I got the hidden values for $_POST and then I pass them to the form but it still has problem here is the sample code: <form method="post" action="" id="myform"> <div id="gridSort"> <input type="hidden" name="selected_sort" value="<?php echo !empty($_POST['sort']) ? strip_tags($_POST['sort']) : ''; ?>" /> <input type="hidden" name="selectionList_view" value="<?php echo !empty($_POST['Listview']) ? strip_tags($_POST['Listview']) : ''; ?" /> <input type="hidden" name="selectionGrid_view" value="<?php echo !empty($_POST['Gridview']) ? strip_tags($_POST['Gridview']) : ''; ?" /> <span>View Results As:</span> <span> <input type="submit" class="listButtons" name="Lisview" value="List"> </span> <span> <input type="submit" class="resultButtons" name="Gridview" value="Grid"></span> <select id="sortSelect" class="sortSelect" size="1" name="sort" onchange="this.form.submit();" > <option selected>Sort</option> <option value="Name">Name</option> <option value="PriceLowToHigh">Price - Low</option> <option value="PriceHighToLow">Price - High</option> </select> </div> </form> <script type="text/javascript"> document.getElementById('sortSelect').value ="<?php if(! $_POST['sort']):?>"Sort"<?php else: echo $_POST['sort']; endif;?>"; </script> <pre> <?php print_r($_POST); ?> </pre> I select the price high to low or something else I want it to remember what I had chosen before that list? or grid? my question is that is it possible to have just 1 form and submit and keep them? hidden field didn't work as I tested. Any help would be appreciated. Sincerely Negin Nickparsa