Re: Why doesn't this code work?

From: Date: Fri, 30 Jan 2015 18:04:29 +0000
Subject: Re: Why doesn't this code work?
References: 1 2 3  Groups: php.general 
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On 2015-01-30 11:39, Abdul Abdul wrote:
Thanks for your reply. I get a blank screen. On Fri, Jan 30, 2015 at 6:33 AM, Ashley Sheridan <ash@ashleysheridan.co.uk> wrote:
On 30 January 2015 14:26:51 GMT+00:00, Abdul Abdul <abdul.sw84@gmail.com> wrote:
I have the following PHP script, where I'm trying to retrieve the image type. Why doesn't it work? What am I doing wrong? <?php $image="4.2.06" $imagetype = exif_imagetype($image); echo "Image type is: " $imagetype; ?>
What does "doesn't work" mean? What output are you getting? Are there any errors or warnings in your logs?
Ash's advice is correct: check your error log. However, I think that one problem is that you don't have a semicolon at the end of the first assignment statement above, which results in a syntax error occurring. Also, please do not top-post. Put your replies at the bottom instead. -- Mark Montague mark@catseye.org

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