Re: Why doesn't this code work?
| From: | Mark Montague | Date: | Fri, 30 Jan 2015 18:04:29 +0000 |
| Subject: | Re: Why doesn't this code work? | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-324339@lists.php.net to get a copy of this message | ||
On 2015-01-30 11:39, Abdul Abdul wrote:
Thanks for your reply. I get a blank screen. On Fri, Jan 30, 2015 at 6:33 AM, Ashley Sheridan <ash@ashleysheridan.co.uk> wrote:Ash's advice is correct: check your error log. However, I think that one problem is that you don't have a semicolon at the end of the first assignment statement above, which results in a syntax error occurring. Also, please do not top-post. Put your replies at the bottom instead. -- Mark Montague mark@catseye.orgOn 30 January 2015 14:26:51 GMT+00:00, Abdul Abdul <abdul.sw84@gmail.com> wrote:I have the following PHP script, where I'm trying to retrieve the image type. Why doesn't it work? What am I doing wrong? <?php $image="4.2.06" $imagetype = exif_imagetype($image); echo "Image type is: " $imagetype; ?>What does "doesn't work" mean? What output are you getting? Are there any errors or warnings in your logs?