Re: Re: PHP Fatal error: Call to undefined function

On 5-3-2015 15:57, Aziz Saleh wrote:

On Thu, Mar 5, 2015 at 9:49 AM, Pete Ford <pete@justcroft.com> wrote:

On 05/03/15 14:42, Maciek Sokolewicz wrote:

On 5-3-2015 13:04, hadi wrote:

Hi, I created function, but im getting error: (PHP Fatal error: Call to undefined function rss1() in C:\phptest\test9.php on line 17)

The error explains it perfectly. You're calling a function which has not been defined yet. So... define your function BEFORE you call it, not AFTER calling it. So <?php function rss1() { ... } rss1(); instead of <?php rss1(); function rss1() { ... } - Tul --- This email has been checked for viruses by Avast antivirus software. http://www.avast.com

There is also the problem is that his function is being defined inside the Exception block (as far as I can tell from the parentheses) which looks weird... --

Peter Ford                            phone: 01580 893333 fax: 01580 893399

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In PHP you can call any function regardless if its before or after, as long as it is within the scope. In your case like Pete mentioned, your function is in your Exception scope. You have 2 options: 1) Please the function outside of the try/catch statement. 2) If you need to keep it within, move it on top of your function call.

I know that, and you know that, but I also know Hadi wouldn't understand this (as is pointed out in the hundreds of other extremely basic questions posted earlier); so attempting to answer his question in the easiest manner possible (undefined? define before using!) was what I was trying to do. Trying to explain scope and runtime evaluation of function definitions isn't something that he would understand (yet) anyway. - Tul --- This email has been checked for viruses by Avast antivirus software. http://www.avast.com