RE: [PHP] Warning: file_get_contents(): Filename cannot be empty

> -----Original Message----- > From: Ashley Sheridan [mailto:ash@ashleysheridan.co.uk] > Sent: Monday, March 09, 2015 11:26 AM > To: hadi > Cc: 'Marcos Almeida Azevedo'; 'PHP General' > Subject: Re: [PHP] Warning: file_get_contents(): Filename cannot be empty > > On Mon, 2015-03-09 at 11:18 +0300, hadi wrote: > > > > > -----Original Message----- > > > From: Ashley Sheridan [mailto:ash@ashleysheridan.co.uk] > > > Sent: Monday, March 09, 2015 10:46 AM > > > To: hadi > > > Cc: 'Marcos Almeida Azevedo'; 'PHP General' > > > Subject: Re: [PHP] Warning: file_get_contents(): Filename cannot be > > > empty > > > > > > On Mon, 2015-03-09 at 10:40 +0300, hadi wrote: > > > > > > > > > -----Original Message----- > > > > > From: Ashley Sheridan [mailto:ash@ashleysheridan.co.uk] > > > > > Sent: Monday, March 09, 2015 10:31 AM > > > > > To: Marcos Almeida Azevedo > > > > > Cc: hadi; PHP General > > > > > Subject: Re: [PHP] Warning: file_get_contents(): Filename cannot > > > > > be empty > > > > > > > > > > On Mon, 2015-03-09 at 15:25 +0800, Marcos Almeida Azevedo wrote: > > > > > > > Hi every one, > > > > > > > > > > > > > > Im getting error while using file_get_contents(): function. > > > > > > > > > > > > > > (Warning: file_get_contents(): Filename cannot be empty) > > > > > > > > > > > > > > Im using file_get_contents(): function to get urls links > > > > > > > from > > > > > > ($convert) > > > > > > > variable. > > > > > > > > > > > > > > Here is my code > > > > > > > > > > > > > > <?php > > > > > > > > > > > > > > > > > > > > > error_reporting(E_ALL); > > > > > > > ini_set("display_errors", 1); > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > $url = > > > > > > > "http://www.sahafah.net/rss.php"; > > > > > > > > > > > > > > > > > > > > > $rss = file_get_contents($url); > > > > > > > > > > > > > > > > > > > > > > > > > I believe file_get_contents should be used on a local file and > > > > > > not remote or over http > > > > > > > > > > You can use file_get_contents() on URLs, but you need to have > > > > > the allow_url_fopen ini setting on, which a lot of shared > > > > > hosting providers won't allow. I don't remember if this is on or > > > > > off by > default. > > > > > > > > allow_url_fopen its on in my system, im using php on windows with > > > apache. > > > > > > > > What about im getting error from file_get_contents()..... > > > > > > > > > > > > > > > > > > I just made a quick test script and this works fine: > > > > > > <?php > > > $url = "http://www.sahafah.net/rss.php"; > > > $rss = > > > file_get_contents($url); > > > > > > var_dump($rss); > > > > > > > > > So it sounds like something on your system. Can you confirm that > > > allow_url_fopen is on (with a phpinfo() call perhaps or an ini_get() > > > call) > > > > > > Next thing to check is the Windows firewall. It could be blocking > > > the outbound call. > > > > > > Ash, > > > > Im ably to get the url data, but im not able to get the image from the url. > > If you see my code you will notice that im grapping the image like > > this, > > > > > $string2 = $item->description; > > > preg_match('/http.*.jpg/',$string2,$match2); > > > > and convert match2 from array to string. > > > > > $convert = implode(",", $match2); > > > > And finally use file_get_contents to get urls image from $convert > > > > // Read image path, convert to base64 encoding > > $imageData = base64_encode(file_get_contents($convert)); > > > > // Format the image SRC: data:{mime};base64,{data}; > > $src = 'data: '.exif_imagetype($convert).';base64,'.$imageData; > > > > // Echo out a sample image > > echo '<img src="', $src, '">'; > > > > > > Ah, as your initial mail just had your entire code and the error with no line > numbers, I assumed the first file_get_contents() call was the issue. > > What happens when you debug your code? What does $convert contain? Is > it a string containing a URL? Yes it containing string full path of url of the image like this (http://www.alsahwa-yemen.net/pic_news/1/1_46777.jpg)