RE: [PHP] is_readable fails with a variable parameter

Also I should mention that I thought that maybe the zip file was not being created in time for this point of my code. But I double checked that that file is there at that point of the code. So again it exists. And if it were the other scenario--permissions--the code would not be able to execute if the file path/name were hard coded. So I'm stumped. Date: Tue, 29 Sep 2015 13:00:55 -0400 Subject: Re: [PHP] is_readable fails with a variable parameter From: azizsaleh@gmail.com To: stpetersn@hotmail.com CC: php-general@lists.php.net Does the actual filename character count match 111? On Tue, Sep 29, 2015 at 12:58 PM, Tommy Peterson <stpetersn@hotmail.com> wrote: string(111) and then the correct path/filename Date: Tue, 29 Sep 2015 12:56:11 -0400 Subject: Re: [PHP] is_readable fails with a variable parameter From: azizsaleh@gmail.com To: stpetersn@hotmail.com CC: php-general@lists.php.net var_dump($file_path_name); What do you get? On Tue, Sep 29, 2015 at 12:51 PM, Tommy Peterson <stpetersn@hotmail.com> wrote: I am using a PHP API that uses is_readable as a check before a particular function does anything. The problem that I am having is that if I do something like is_readable($file_path_name); my code terminates as is_readable says it cannot read the file or there is a permissions issue. But if I go to the file path/name in $file_path_name (echoing it out to make sure) I can see and open the file. If I edit the same code and do something like is_readable("/path/to/the/file/filename.zip") the same code executes just fine. At first I thought the variable was some how getting over written. But it isn't. It is just somehow the variable is not be interpolated correctly by is_readable like a hard coded path/file name is. Any thoughts? This is on Linux. And this is PHP 5.4.43