Re: Calling a program

On 30 November 2015 18:27:37 GMT+00:00, Curtis Maurand <curtis@maurand.com> wrote: > >you can include the p7a.php in your script or you can >shell_exec(p7a.php) > >$script_result = shell_exec('p7a.php'); > >There is a lot of useful information here once you get past the snide >comments at the top. > >http://stackoverflow.com/questions/8450696/execute-a-php-script-from-another-php-script > > > >On 11/29/2015 11:36 PM, Ethan Rosenberg wrote: >> Dear List - >> >> Can you not call a PHP script from a form -- action = 'program.php'? > >> In my hands it does not work... >> >> >> I have tried the following >> >> include program.php; >> >> later in the program ... >> >> form >> . >> . >> >> echo "<input type='hidden' name='next_step' >> value='step14' />"; >> >> . >> . >> . >> . >> >> switch ( $_POST['next_step'] ) >> { >> >> case 'step14': >> { >> P7a.php(); >> } } >> >> } //end Switch >> >> The result of this is that program.php runs at the start of the >> script, and step14 is never called. >> >> I am totally confused. >> >> If you need more details, please specify. >> >> TIA. >> >> Ethan >> shell_exec is *not* the right method here. As others have pointed out, it appears there's a lack of understanding about how the PHP stack works with regards to requests and logic. Thanks, Ash -- Sent from my Android device with K-9 Mail. Please excuse my brevity.