Re: detecting leap years?

> On Jan 19, 2018, at 5:42 PM, Jeffry Killen <jekillen@prodigy.net> wrote: > > >> On Jan 19, 2018, at 5:36 PM, Aziz Saleh <azizsaleh@gmail.com> wrote: >> >> function is_leap_year($year) { >> >> >> return ((($year % 4) == 0) && ((($year % 100) != 0) || (($year % 400) == 0))); >> } > > Thank you; > Jeff k > Thank you Richard for Or the "L" parameter: L Whether it's a leap year -- 1 if it is a leap year, 0 otherwise. on the date() function: This is helpful to know in the future. Meanwhile, I modified the original code in reply to the following to work in my situation 1: I couldn't seem to get a decisive response from code as posted in reply were 2018 is from getDate return array print is_leap_year(2018) // ... nothing, no false, -1, 0 or anything. also no complaints 2: I have had problems with using % alone in php, and reading the manual it didn't actually do what it does in javascript: 2.5%1 = .5, so I used fmod I wrote a bunch if code in javascript and did an almost verbatim translation to php. But every where I used % in the javascript code, I had to use fmod in php to get the same result. 3: If the $year value comes in as a string so I didn't want to trust that it would be coerced to number type. 4: The return doesn't have to be a string, it is a left over from processing string representation of boolean value, as would be sent in a $_GET var. function getLeap($year) { settype($year, 'int'); if( ( fmod($year, 4) == 0 ) && ( ( fmod($year, 100) != 0 ) || (fmod($year, 400) == 0) ) ) { return 'true'; } else { return 'false'; } } I hope this considered something of value to list in general. It is not intended as a criticism of the code offered. I was probably missing some key understanding. Jeff K