Re: In php 8.0: unable to distinguish between instance variable beingnull and unset

From: Date: Sat, 04 Sep 2021 19:29:33 +0000
Subject: Re: In php 8.0: unable to distinguish between instance variable beingnull and unset
References: 1  Groups: php.general 
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Emiel Mols wrote on 9/3/21 07:08: > Hello, > > Our codebase depends on distinguishing whether an instance variable is > unset, or simply null: > > class C { public int $v = 123; } > $x = new C; unset($x->v); > $y = new C; $u->v = null; > > In php <8.0 we made this work with @array_key_exists($x, 'v'), which > stopped working. isset($x->x) doesn't work, as it will return true for > 'null' as well. property_exists($x, 'v') will always return true as long as > the variable is declared: php-src here > > <https://github.com/php/php-src/blob/a13730c5e465b3c349a7970d15a49e4e132d4e07/Zend/zend_builtin_functions.c#L943> > . > > Apart from using debug_zval_dump (too expensive), any hints? This feels > like quite the oversight honestly :). > > Best, > > Emiel > If you use public int $v, there shouldn't be a way to set it null, unless I'm missing something. https://3v4l.org/nNDq4 Cheers, Ben

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