Re: How can I replace $_SERVER["DOCUMENT_ROOT"] in PHP 7.0?

On Mon, 13 Sep 2021 20:36:35 +0100, Ashley Sheridan <ash@ashleysheridan.co.uk> wrote: >> include_once ('appdbdata.php'); >> >> THen seemingly all worked, but only until a call was made to a php file at a >> deeper location which also included this file... >> >Have you looked at __DIR__ ? >https://www.php.net/manual/en/language.constants.magic.php Yes, I have tested this php file located in the htdocs/ dir: <?php ini_set('display_errors', '1'); set_include_path(get_include_path().PATH_SEPARATOR.dirname($_SERVER['DOCUMENT_ROOT'],1)."/php"); include ('logindata.php'); echo "Including: " .dirname($_SERVER['DOCUMENT_ROOT'],1)."/php/logindata.php"; echo "<br>Mail sender= " . $mailsender ; echo '<br>Dir= ' . __DIR__ ; echo "<br>DocRoot= " . dirname($_SERVER["DOCUMENT_ROOT"],1) . "/"; ?> The output was this: Including: /usr/services/vux/apache/php/logindata.php Mail sender= Dir= /data/25/2/158/91/2484743/user/2721122/htdocs DocRoot= /usr/services/vux/apache/ The strange thing is that even though I have set include_path according to the selected solution in this stackoverflow thread: https://stackoverflow.com/questions/44984560/what-is-the-php7-version-of-serverhome it does not pick up the logindata.php file where $mailsender is defined. If I move the test php file into /php then it picks up the information since it is in the same dir. Note that __DIR__ and dirname($_SERVER['DOCUMENT_ROOT'],1) return completely different paths! It really seems very strange that they have removed this function without supplying a new version... -- Bo Berglund Developer in Sweden