Re: #!/path/to/php at top of output from CGI

Normal CGIs exucute just fine... C or perl or whatever. And I did a phpinfo() call and it outputted as normal, just with a '#!/usr/local/bin/php' at the top. Thanks, Jeff Davis On Thu, 04 Jan 2001, you wrote: > It sounds like the webserver is not executing it - make sure you have a > ScriptAlias directive for the directory you're trying to put it into. If you > don't want it to be restricted to a ScriptAlias'd directory, you'll need to > allow cgi execution outside it with Options ExecCGI. Check the Apache manual > to be sure, and be aware of the security implications of running executables > outside a ScriptAlias'd directory. > > jason > > > > I compiled a version of php-4.0.4 as a cgi (I already installed a module > > version, but I need a CGI too). When I make a file I put > #!/usr/local/bin/php > > at the top and chmod 755 to make it a valid cgi. Then I name it with a > .cgi > >> extension, and put it in the right directory. When I execute it from the > shell > > I get normal output, with no #!/usr/local/bin/php anywhere in the output. > > However, when I run it as a CGI through a browser, I get a > #!/usr/local/bin/php > > at the top of the output. I have no idea how to make it stop doing that, > but I > > need to offer CGI execution for the sake of security (I use suEXEC). > > > > Thanks, > > Jeff Davis > > -- > > Jeff Davis > > jdavis@dynworks.com > > http://dynworks.com -- Jeff Davis jdavis@dynworks.com http://dynworks.com