Re: Different images getting saved to the same file??? (ImageJPEG)

Could you give me an example? My problem is I output a lot of HTML before the image, so I imagine I have to split my code into 2 files, one where I generate the image (lets say stored into variable $pic), and then issue an <img src= ...> tag passing as parameter the name of the file that actually generates the image. Something like: echo "<img src=\"./file_that_actually_shows_the_image.php?image=$pic\" border=\"0\" />"; And in file "file_that_actually_shows_the_image.php" I would have something like: <? Header("Content-type: image/jpg"); ImageJPEG($pic); ImageDestroy($pic); ?> But then I only got the following HTML output: <img src="./file_that_actually_shows_the_image.php?image=Resource id #1" border="0" /> Or maybe I should reference the file as: <img src="./file_that_actually_shows_the_image.php?barcode=2759100000004467870090 1008765010000000040001" border="0" /> and then inside "file_that_actually_shows_the_image.php" I would do all the calculations to generate the image from the number passed as parameter and then output the image like below: <? Header("Content-type: image/jpg"); ... Here I get the value of the barcode parameter, either using HTTP_SERVER_VARS["argv"] or maybe 'urldecode'; Secondly I perform the algorithm to actually generate the image into variable $pic ... ImageJPEG($pic); ImageDestroy($pic); ?> I tried that but I also only got a broken image (the referenced PHP file did not get interpreted): <img src="./file_that_actually_shows_the_image.php?barcode=2759100000004467870090 1008765010000000040001" border="0" /> What is the correct way to do that? Thanks, Paulo ----- Original Message ----- From: Matt Whipple <brendel@adelphia.net> To: Paulo Parola <php@brazilinfo.com>; PHP List <php-general@lists.php.net> Sent: Sunday, January 07, 2001 8:13 PM Subject: Re: [PHP] Different images getting saved to the same file??? (ImageJPEG) > If you don't have to save the files then why not just output to the browser > without writing a file? > -Matt > > At 07:53 PM 1/7/2001 -0200, Paulo Parola wrote: > >I am creating a barcode using function ImageJPEG as below: > > > > ImageJPEG($picture,"./temp/graph.jpeg"); > > > >The image created is different according to the values informed by the > >user in a form. A file named 'graph.jpeg' is created in directory > >'temp' > >and the image is shown to the user when he submits the form. > > > > > >Now, how can I be sure that some user is not going to have the image > >resulting from some other user's form submission shown at his browser if I > >always specify the same filename for the image created? > > > >==> Do I have to create different image filenames, lets say by naming the > >image files after some combination of the user's Session ID or IP address? > > > > And then (if this is the case) how should I get rid of the files created > > on the hard disk? > > > >Thanks, > >Paulo > > >