Re: PHP newbie question

since when is false equal to one? in PHP, false is represented by string(0) "", and true by 1. so, you really want <?php if (! $a) print !$a; ?> At 19:33 10.1. 2001, Neil Zanella wrote the following: -------------------------------------------------------------- >On Wed, 10 Jan 2001, Toby Butzon wrote: > >> : <?php if (! $a) print "Hello, World!"; // script 2 ?> >> >> $a evaluates to false, the ! reverses it, and it prints "Hello, World!" > >What is bothering me is the following: if variables that are not assigned >a value were to evaluate to false then since false is the same as the >number 1 the following PHP script should print the number 1 but instead >prints nothing: > ><?php if (! $a) print $a; ?> > >How is this behavior justified? >I could not find anything on this in the PHP manual. > >Thanks, > >-- Neil > > >-- >PHP General Mailing List (http://www.php.net/) >To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net >For additional commands, e-mail: php-general-help@lists.php.net >To contact the list administrators, e-mail: php-list-admin@lists.php.net ------end of quote------ ____________________________________________________________ Cynic: A member of a group of ancient Greek philosophers who taught that virtue constitutes happiness and that self control is the essential part of virtue. cynic@mail.cz