Re: output the var $ name

From: Date: Wed, 28 Jun 2000 02:58:17 +0000
Subject: Re: output the var $ name
References: 1  Groups: php.general 
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On 27 Jun, Matthew M. Boulter wrote: about echo 'The variable $foo equals: '.$foo; > Wouldn't that output > > The variable bar equals: bar > > not actually > > The variable $foo equals: bar > > I want to delimit the parser from parsing the variable when I'm describing > it's name. > If you check out www.php.net/manual/language.types.string.php or your favourite mirror, you'll see among other things that variables aren't expanded inside single quotes. Cheers -- David Robley | WEBMASTER & Mail List Admin RESEARCH CENTRE FOR INJURY STUDIES | http://www.nisu.flinders.edu.au/ AusEinet | http://auseinet.flinders.edu.au/ Flinders University, ADELAIDE, SOUTH AUSTRALIA

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