Re: date problem: some months have 5 weeks... how I discoverwhich ones?

> For a newspaper, a week start on sunday and ends in a saturday. > > Media planners divide ads in newspapers by monhs and than by weeks, > respectively. Well, this _seems_ contradictory to your original "definition", but I got it. > so let's say: > > january 2001 started in a monday > > Su Mo Tu We Th Fr Sa > 1 2 3 4 5 6 - 1st week > 7 8 9 10 11 12 13 - 2nd week > 14 15 16 17 18 19 20 - 3rd week > 21 22 23 24 25 26 27 - 4th week > 28 29 30 31 - 5th week Well, get the timestamp of the first of the month: $ts = mktime(0,0,0,1,1,2001); then add 7 days worth of secnds to it until the month is no longer January: while ((int)date('m',$ts) == 1) { //do stuff for this week $ts += (60*60*24*7); } > So january is a month that has 5 weeks for a newspaper, because if I would > put an ad on a tuesday, january has 5 tuesdays.. got it? > > How do I do to calculate that? I hope this help. It should give you the general idea. I don't have time to write your whole application. ;-) Hopefully I gave you enough to get you going in the right direction. Ultimately you are going to need to cutomize this for what you exactly want to do. Jeremy Jeremy Brand :: Sr. Software Engineer :: 408-245-9058 :: jeremy@nirvani.net http://www.JeremyBrand.com/Jeremy/Brand/Jeremy_Brand.html for more - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - "LINUX is obsolete" -- Andy Tanenbaum, January 29th, 1992 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - http://www.JEEP-FOR-SALE.com/ -- I need a buyer Get your own Free, Private email at http://www.smackdown.com/