Re: Variable method

At 4:53 PM -0800 1/18/01, Blaine Grady wrote:

Suppose I have:

     $method = "doIt";

inside a class. How do I construct the statment, using $method, to call:

     $this->doIt();

I tried every combination I can think of but I keep getting "Call to unsupported or undefined function" when doIt() is a proper method. I have no problem with standard functions. Thanks for any help.

Did you think of class foo { function bar() { $method = 'doIt'; $this->$method('yes'); } function doIt($Answer) { echo "Noodles are happy? $Answer"; } } It's been awhile, but I believe that should work. If not, give us more info: What version of PHP? What, exactly, DID you try? - steve -- +--- "They've got a cherry pie there, that'll kill ya" ------------------+ | Steve Edberg University of California, Davis | | sbedberg@ucdavis.edu Computer Consultant | | http://aesric.ucdavis.edu/ http://pgfsun.ucdavis.edu/ | +-------------------------------------- FBI Special Agent Dale Cooper ---+