RE: [PHP] MySQL Query Error
| From: | Matt Stone | Date: | Mon, 22 Jan 2001 05:23:48 +0000 |
| Subject: | RE: [PHP] MySQL Query Error | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-35954@lists.php.net to get a copy of this message | ||
No, that is exactly as the PHPLib Debug function is returning... :|
-----Original Message-----
From: Samantha Savvakis [mailto:samantha@cfs.net.au]
Sent: Monday, 22 January 2001 3:21 PM
To: Matt Stone
Subject: RE: [PHP] MySQL Query Error
I'm not sure why are getting that error.
Is the statement you are running exactly the same as the one posted in the
email? Check that you don't have a "comma" after the "images i" part. If i
put a comma there, I can simulate your error. Otherwise, your syntax to me
seems fine.
> -----Original Message-----
> From: Matt Stone [mailto:matt@planetveggie.com]
> Sent: Monday, 22 January 2001 15:01
> To: PHP List
> Subject: [PHP] MySQL Query Error
>
>
> Hi,
> I have a MySQL statement, namely:
> SELECT COUNT(*) AS Count FROM images i LEFT JOIN categories c ON
> i.cat_id=c.id LEFT JOIN subcategories s ON i.subcat_id=s.id
>
> I want to change the LEFT JOINs to INNER JOINs like so:
> SELECT COUNT(*) AS Count FROM images i INNER JOIN categories c ON
> i.cat_id=c.id INNER JOIN subcategories s ON i.subcat_id=s.id
>
> But as soon as I do that I get this error message:
> MySQL Error: 1064 (You have an error in your SQL syntax near 'INNER JOIN
> categories c ON i.cat_id=c.id INNER JOIN subcategories s ON i.subcat_' at
> line 1)
> Session halted.
>
> Help please. Thanks,
>
> Matt Stone
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