RE: [PHP] mysql_insert_id()
| From: | Boget, Chris | Date: | Wed, 24 Jan 2001 21:19:49 +0000 |
| Subject: | RE: [PHP] mysql_insert_id() | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-36477@lists.php.net to get a copy of this message | ||
> When you are using mysql_insert_id, you don't want to pass it
> the result of your previous SQL statement as in:
> $result = mysql"mydb", "My SQL statement", $my_connect) ;
> $last_id = mysql_insert_id($result)
This is what it sounds like it's looking for in the documentation. It
could be just how I'm reading it. :p
> Rather, you want to pass it the link identifier from your
> mysql_connect like:
> $result = mysql("mydb", "My SQL statement", $my_connect) ;
> $last_id = mysql_insert_id($my_connect)
Tried this, too, with no luck. :( I'm using mysql_pconnect() and
mysql_connect() and neither seems to help my situation.
Chris