Re: multiple function returns

$array[0] will be the lang_pref and $array[1] will be the currency_pref. Jeremy Jeremy Brand :: Sr. Software Engineer :: 408-245-9058 :: jeremy@nirvani.net http://www.JeremyBrand.com/Jeremy/Brand/Jeremy_Brand.html for more - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - "LINUX is obsolete" -- Andy Tanenbaum, January 29th, 1992 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - http://www.JEEP-FOR-SALE.com/ -- I need a buyer Get your own Free, Private email at http://www.smackdown.com/ On Thu, 25 Jan 2001, Jamie wrote: > Date: Thu, 25 Jan 2001 13:04:27 +0800 > From: Jamie <jssmith@echidna.stu.COWAN.EDU.AU> > To: PHP <php-general@lists.php.net> > Subject: [PHP] multiple function returns > > Can anyone help me I'm trying to read two results from a function by passing > them out via an array but I'm not sure how to access them once I have done > that. In the PHP manual it shows a list call which I can't seem to even find > what the hell it does the code below runs without any errors but does not > seem to work. > > here the function gest passed the language and currency preference and a > variable (1,0) to decide what it will do with them - update the preferences > of the user or read out and define the preferences. (once updated I want it > to read out the prefs aswell) > > function PrefChange($lang,$curry,$state){ > global $DB_Server, $HTTP_Host, $DB_Login, $DB_Password, $DB_Name, $DocRoot ; > > if ($state){//read preferences from page > if (!($result = mysql_db_query($DB_Name,"SELECT language_pref, > currency_pref FROM users WHERE user_id ='$cookie_user'"))){ > DisplayErrMessage(sprintf("internal error %s %s %s %d:%s\n",$DB_Server, > $DB_Login, $DB_Password, > mysql_errno(), mysql_error())); > while ($row = mysql_fetch_array($results)){ > $lang_pref = $row["language_pref"]; > $currancy_pref = $row["currency_pref"]; > return array($lang_pref,$currancy_pref); > } > } > } else {///update preferences from page > if (!($result = mysql_db_query($DB_Name,"UPDATE users SET > language_pref='$lang' AND currency_pref='$curry' WHERE > user_id='$cookie_user'"))){ > DisplayErrMessage(sprintf("internal error %s %s %s %d:%s\n",$DB_Server, > $DB_Login, $DB_Password, > mysql_errno(), mysql_error())); > PrefChange(0,0,1) ; > } > } > } > > > an example of what I'd like to do when calling the function (here I'm only > reading the prefrences from the DB ), a select box that is showing the > preference that is chosen with the preference read from the above function > and the list created by the function below > > <select name="form_lang_pref" style="font-family:verdana, > Arial;font-size:8pt" CLASS:menu"> > <? > list ($form_language_pref, $form_currency_pref) = PrefChange(0,0,1); > > $select_id = $form_language_pref; > $db = mysql_connect("$DB_Server", "$DB_Login, $DB_Password"); > mysql_select_db("$DB_Name",$db); > $results = mysql_query("SELECT * FROM language ORDER BY language > ",$db); > > while ($row = mysql_fetch_array($results)){ > $rowid = $row["language_id"]; > $name = $row["language"]; > if ($rowid == $select_id) { > echo("<option SELECTED > value=\"$id\">$name</option>\n"); > } else { > echo("<option > value=\"$id\">$name</option>\n"); > } > // endwhile; > } > echo("</select>"); > ?> >