Re: trouble with a query object

> $nameArray = array("Last", "Suffix", "Prefix", "First", > "Middle"); > while (list($key, $value) = each ($nameArray)){ > if ($infoObject->$value != ""){ > echo "$infoObject->$value"; #this is the problem line... > } > } > ************ > > If I take out the "$infoObject->" on the problem line, the correct value is > displayed. But while "$infoObject->" is present, the error is given. I > assumed that $value would be a string since the array is of strings. If I > used mysql_fetch_array and used $value for the index of the array, would the > same thing happen? Thanks for the help. Try getting rid of the quotes in your problem line, and then switch to mysql_fetch_array if that doesn't help. -- Visit the Zend Store at http://www.zend.com/store/ Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm Volunteer a little time: http://chatmusic.com/volunteer.htm