Re: Chopping up a comand line return.
| From: | Juan | Date: | Fri, 02 Feb 2001 15:23:20 +0000 |
| Subject: | Re: Chopping up a comand line return. | ||
| References: | 1 2 3 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-37850@lists.php.net to get a copy of this message | ||
Try this :
<?php
$fp = popen ("/bin/ls ", "r");
while(!feof($fp))
{$buffer = fgets($fp,4096);
echo "\n<br><li> <a
href=".chr(34).$buffer.chr(34).">".$buffer."</a>";}
pclose($fp)
?>
s> Here is my problem,
s> I want to read the contents of a dir, on a linux machine, in proper order
s> according to date (ie. from newest to oldest). My problem is I know how to
s> do it in perl....but not in php. I tried what I use is perl and it doesn't
s> work. Here is what I have that does work.
s> $stuff =
ls -C1t /your/dir/to/read/from/$author/; ---works
s> now I want to parse up $stuff to get the 10 or so files names so I can link
s> to them. I just
s> cannot figure out how to do it in php.
s> This is how I would do it in perl/CGI
s> @stuff = same as above
s> foreach $filename (@stuff){
s> next if $filename !~ /(inc$/i;
s> print = "<a href=\"$author/$filename\">$filename</a>";
s> }
s> I need something pretty much the same in php...I just don't know why it
s> isn't working quite the same......
s> thanks for your time in advance.,
s> nixter
s> -----------------------------------------------------------
s> Nick.Stankus
s> Software Engineer
s> Logicon/Sterling Federal
s> 402-232-7870
s> -----------------------------------------------------------
s> "There are two things that are infinite; Human stupidity and the
s> universe. And I'm not sure about the universe." - Albert Einstein
_______________________________________
Massuelles Jean-Baptiste(Juan@acomme.fr)
Société A Comme...
Tel : 03 80 700 702