Re: Passing an array as an argument.

On Tuesday 06 February 2001 18:18, April wrote: > How do you pass an array as an argument to a function? Just as any other variable. Read on... > function process_members($asker_rank, $email) { > > global $database_mysql; > mysql_select_db($database_mysql); > > while (list ($key, $val) = each ($email)) { > echo "$key => $val<br>"; > } > > } > ######### Doing the same thing with the function here returns this > error, though. ######## > // Warning: Variable passed to each() is not an array or object in > lib.inc on line 447 > process_members($asker_rank, $total_members, $email); Look at the definition of process_members() again. The function takes two values. The first is called $asker_rank and the second $email. Now you pass *three* values to it. #1, $asker_rank, is fine. But #2, $total_members, is passed in place of $email, so every time the function body accedded its "$email" parameter, it gets the value of $total_members - which is not an array. The third parameter is ignored. -- Christian Reiniger LGDC Webmaster (http://sunsite.dk/lgdc/) "Software is like sex: the best is for free" -- Linus Torvalds