Re: Odd question regarding creating a php file

From: Date: Wed, 07 Feb 2001 14:16:36 +0000
Subject: Re: Odd question regarding creating a php file
References: 1 2  Groups: php.general 
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In reply to Chris. The reason I'm having this page created is because people will need to be able to see this person's "win/loss" record. I have a script that displays all of the ppl registered and when you view their page, you can get a real time report on their ratings. As another alternative: I could pass the variables into a 'template' page and create it from there, but I didn't want all my links to be buttons with hidden variables in them. I hope I cleared that up. Thanks for your help Dusten "Chris Lee" <lee@mediawaveonline.com> wrote in message news:95q4hi$b9u$1@toye.p.sourceforge.net... > there are a few errors in here. number one being this. > > echo "... mysql_query("SELECT ..."; > > do you see it? youve got the " in the middle there, that is ending your " " > section, not what you wanted right. second too is the fact anything in " " > will be evaluated, anything in ' ' will not. > > fwrite($fp, '<?php $result = mysql_query("SELECT * ... "); ?> <html> > ... > </html>'); > > In the future I find if your having a problem with a string, echo it to the > screen, see what happens. > > Got a question for you, what is this next page for? im curious why you are > opting todo this this way. are you trying to get around sending variables > through POST/GET/COOKIES ? I would highly recommed sessions if this is your > idea. Speed and Easy of use will be greatly increased. Please respond back > with your answer, Im curious. > > > -- > > > > Chris Lee > Mediawaveonline.com > lee@mediawaveonline.com > > > > > > ""Dusten"" <dusten@gofrontline.com> wrote in message > news:95q1bv$ekv$1@toye.p.sourceforge.net... > > I'm having trouble creating a php file. I've tried to explain it to the > > peeps in IRC but am having trouble. It'll be easier to paste my code: > > ... > > $result2 = mysql_query("INSERT INTO winLoss(login, pass) > > VALUES('$login', '$pass')"); > > > > if($result2) > > { > > $fp = fopen > ("/home2/colorado/public_html/profiles/$screen_name$ext", > > "w"); > > fwrite($fp, "<?php > > $result = mysql_query("SELECT * from winLoss WHERE > > login='$login' AND pass='$pass'"); > > ?> > > > > <html> > > <head> > > <title>$screen_name</title> > > </head>")......... > > > > Ive ommited the redundant things. Basicly it just creates this: SELECT * > > from winLoss WHERE login='' I need that value in there. Any ideas? > > > > Thank you (sorry about the repost) > > Dusten > > > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > > For additional commands, e-mail: php-general-help@lists.php.net > > To contact the list administrators, e-mail: php-list-admin@lists.php.net > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >

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