Re: include("blah.php?var=this"); doesn't work?!

From: Date: Thu, 08 Feb 2001 17:34:32 +0000
Subject: Re: include("blah.php?var=this"); doesn't work?!
References: 1  Groups: php.general 
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Uh, why? Adding ?asin$asin makes absolutely no sense in an include since included files share the same namespace as the parent file. You can simply do: $asin = 123; include 'book_reviews.php'; And the $asin variable will be accessible to you book_reviews.php script. -Rasmus On Thu, 8 Feb 2001, John Vanderbeck wrote: > I need to be able to do: > > <? > if (isset($asin)) > { > include("book_reviews.php?asin=$asin"); > } > else > { > include("book_reviews.php"); > }?> > > This is embeded in one of my sites pages..However, the call with the var > added on won't work, it seems like its looking for a file with that whole > name. Does anyone know how I can do this? > > - John Vanderbeck > - Admin, GameDesign > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >

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