RE: [PHP] comparisons

try this first: if((strlen($pick1)==strlen(pick2))and($pick1==$pick2)) echo 'they are equal'; else echo 'they aren\'t at least in length'; However, it seens to me as a very slicky style ... whay not to make them somehow different .... let's say using an array, or having a letter instead of 0 ... Sincerely, Maxim Maletsky Founder, Chief Developer PHPBeginner.com (Where PHP Begins) maxim@phpbeginner.com www.phpbeginner.com -----Original Message----- From: Curtis Maurand [mailto:curtis@canon.maurand.com] Sent: Monday, February 12, 2001 3:48 AM To: php-general@lists.php.net Subject: [PHP] comparisons Hello, I'm having a rather strange problem. I'm trying to compare two values. "01" and "1". The variables names that they are submitted under are pick1 and pick2. i use the following code $mypick1 = strval($pick1); $mypick2 = strval($pick2); I then perform the following comparison: if ($mypick1 == $mypick2) { $error = 1; $errorstring[1] = "Your first pick and second pick are the same."; } However, I get the error that they are equal. If I call the comparison as foloows: if(strval($mypick1) == strval($mypick2) { $error = 1; $errorstring[1] = "Your first pick and second pick are the same."; } I still get the error. Anyone have any ideas? These two valuse mustbe evaluated as different. Thanks in advance Curtis