Re: Broken icon?

I am doing the same with the following code $rec1=@mysql_fetch_object($result); $image=$rec1->iurl; $alt=$rec->mnam; $array=GetImageSize("image/$image"); echo "<img src='image/$image' alt=$alt border=0 align=left $array[2]>"; and it works a charm. Malouin Design Graphique wrote:

Hello, My problem is that I have in the table below an URL (see $indice_url) that points to the graphic (.gif) that has to be use by the the "$indice" variable. The graphics ( five different ones) located in the same folder as the script " data_out.php3" Any Guru out here could shred me the "Blue Light" on how to make the images to show? Thanks in advance, Best regards, Yves This is the table that feeds: -------------------------------- CREATE TABLE indice ( id int(11) DEFAULT '0' NOT NULL auto_increment, date text, indice text, indice_url varchar(255), PRIMARY KEY (id) ); -------------------------------- The file to get the data out: -------------------------------- <?php /* data_out.php3 */ $db = mysql_connect("www.server.com", "root", "password"); mysql_select_db("db_name", $db); $sql = "select * from table_name order by 'date'"; $sql = "select * from table_name"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { print("<tr><td bgcolor=\"#003399\">"); printf("<img src=\"$indice_url\">%s</td></tr>\n", $row["indice_url"]); } ?> -------------------------------- The output that it gives me (in source mode): -------------------------------- <table border="1" cellpadding="3" width="130">

    <tr><td bgcolor="#003399"><img src="">image_f03.gif</td></tr>
    <tr><td bgcolor="#003399"><img src="">image_f05.gif</td></tr>
    <tr><td bgcolor="#003399"><img src="">image_f01.gif</td></tr>

</table> --------------------------------