RE: [PHP] parse error driving me nuts ...
| From: | Jon Haworth | Date: | Thu, 15 Feb 2001 15:38:25 +0000 |
| Subject: | RE: [PHP] parse error driving me nuts ... | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-39915@lists.php.net to get a copy of this message | ||
Instead of
if ((mysql_num_rows($result)) = 1)
try
if ((mysql_num_rows($result)) == 1)
HTH
Jon
-----Original Message-----
From: Andrew [mailto:andrew@salamander.net]
Sent: 15 February 2001 15:34
To: php-general@lists.php.net
Subject: [PHP] parse error driving me nuts ...
hi, can anyone help me spot the parse error?
It's throwing up on the first "if" line, and for the life of me I cannot
find it! :)
tia,
andrew
<?php
include("db_connect_params.inc");
$sql="select path from PHOTO where pid =1";
$link_id = mysql_connect($host, $usr, $pass);
$result = mysql_db_query($database, $sql, $link_id) or die("no result");
if ((mysql_num_rows($result)) = 1)
{
$row=mysql_fetch_array($result);
extract($row);
echo "<img src =\"$path\"></img><br>";
} else {
if (!isset($ii)) $ii = 1;
$i = 1;
while($row=mysql_fetch_array($result))
{
extract($row);
$displayed[$i]=$path;
echo "<a
href=\"$PHP_SELF?ii=$i\">$i</a>  ";
$i++;
}
echo "<img src =\"$displayed[$ii]\"></img><br>";
}
?>
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