Re: How to inverse the date sorting [IT WORKS! - THANKS!]
| From: | Malouin Design Graphique | Date: | Thu, 15 Feb 2001 17:47:16 +0000 |
| Subject: | Re: How to inverse the date sorting [IT WORKS! - THANKS!] | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-39953@lists.php.net to get a copy of this message | ||
Just as simple as that?!
Thank you guys: Fang; Andrew and Joe.
Much appreciated.
Hope to be able to give a hand myself someday to newbies like me ;-)
Won't have to ask this question again. Promessed!
Mes salutations,
Yves
At 12:26 -0500 15/02/2001, Fang Li wrote:
add DESC after order by 'date', it will be $sql = "select * from table_name WHERE TO_DAYS(NOW()) - TO_DAYS(date) <= 21 order by 'date' DESC"; Fang -----Original Message----- From: Malouin Design Graphique [mailto:lists@malouin.qc.ca] Sent: February 15, 2001 12:15 PM To: php-general@lists.php.net Subject: [PHP] How to inverse the date sorting Hello, Anybody here would know, how I could inverse the date sorting or ordering? This script below gives me for example: 2001-01-01 2001-01-15 2001-01-31 and so on... when I wish it would gives me: 2001-01-31 2001-01-15 2001-01-01 and so on... --------------------------------------------- <?php $db = mysql_connect("servername.com", "root", "password"); mysql_select_db("stats", $db); $sql = "select * from table_name WHERE TO_DAYS(NOW()) - TO_DAYS(date) <= 21 order by 'date'"; $result = mysql_query( $sql ); while ( $row = mysql_fetch_array( $result ) )-- ------------------------ Malouin Design Graphique http://www.malouin.qc.ca Québec (Québec) CANADA{ echo "<tr><td><span class=\"size1\"><b>$row[date]</b><br><imgsrc=\"$row[indice_url]\"><br>$row[indice]<hr noshade size=\"1\"></span></td></tr>\n";}?> --------------------------------------------- Thanks again for your help. Merci beaucoup, Yves