RE: [PHP] Tough one?
| From: | Shawn Esplin | Date: | Wed, 21 Feb 2001 20:17:23 +0000 |
| Subject: | RE: [PHP] Tough one? | ||
| Groups: | php.general | ||
| Request: | Send a blank email to php-general+get-41059@lists.php.net to get a copy of this message | ||
I'm not sure this is the best way to do it, but you could try:
$keys = array_keys($HTTP_POST_VARS);
for($x = 2; $x < (count($keys) - 1); $x++)
{
$updateString=$updateString.$keys[$x]."='".$HTTP_POST_VARS[$keys[$x]]."',";
}
$x++;
$updateString=$updateString.$keys[$x]."='".$HTTP_POST_VARS[$keys[$x]]."'";
or:
$keys = array_keys($HTTP_POST_VARS);
for($x = 2; $x < count($keys); $x++)
{
if($x != (count($keys) - 1))
{
$updateString=$updateString.$keys[$x]."='".$HTTP_POST_VARS[$keys[$x]]."',";
}
else
{
$updateString=$updateString.$keys[$x]."='".$HTTP_POST_VARS[$keys[$x]]."'";
}
}
-----Original Message-----
From: Mike [mailto:mpeloso@princeton.edu]
Sent: Wednesday, February 21, 2001 11:34 AM
To: php-general@lists.php.net
Subject: [PHP] Tough one?
I am building an update string on the fly from form fields.I am trying to
add a comma between fields but I cant have one after the last field.This is
the code that doesnt work.Also I cant have a comma at all in a table with
only one updated field.
$keys = array_keys($HTTP_POST_VARS);
for($x = 2; $x < count($keys); $x++)
{
$updateString=$updateString.$keys[$x]."='".$HTTP_POST_VARS[$keys[$x]]."',";
Thanks
Mike
mpeloso@princeton.edu
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