RE: [PHP] array headaches

<snip> > Why do you need to put the values in an array, then read through the > array to print the values? Why not just print each record as you get it > from the DB? The array is formed before the page is called. This is then passed to the page which prints it out. M@ > On Thu, 22 Feb 2001 02:11, Matt Williams wrote: > > I have done it this way... > > > > $menu = array(); > > $count = $db->num_rows(); > > for($i = 0; $db->next_record(); $i++) > > { > > $menu[$i]["name"] = $db->f("name"); > > $menu[$i]["url"] = $db->f("topic_id"); > > } > > > > OK, so is there a better way of acheiving the same end result? > > and this is what I've got to print the results > > > > while ( list($name, $subarray) = each($menu) ) > > > > > > echo "<a > > > > href=\"".$subarray["url"]."\">".$subarray["name"]."<a><br>\n"; > > > > } > > > > is there any better way of doing this?? > > > > thanks > > > > M@ > > > -- > David Robley | WEBMASTER & Mail List Admin > RESEARCH CENTRE FOR INJURY STUDIES | > http://www.nisu.flinders.edu.au/ > AusEinet | > http://auseinet.flinders.edu.au/ > Flinders University, ADELAIDE, SOUTH AUSTRALIA > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >