Re: Content-Type: image/gif and send the image in hex

On Sunday 04 February 2001 05:53, you wrote: > Hi all, > > I'm trying to make a demonstration script (using PHP) that demonstrates > the use of MIME types in HTTP headers. It should send the Content-Type > header and than sends an image to the browser in hex. What do you mean with "in hex"? Hex is a number system. It only exists to make handling binary data easier for humans. > I run the script in my browser and get the bare decimal values > displayed and not the GIF image: Aha. So you just want to "send the image". > I also tried to use: > header("Content-type: image/gif"); > But no success. > I don't want to use the header() function cause it doesn't help my > demostration script show the workings. Well, you *need* the header ("Content-type: image/gif"); to tell the browser that you're sending a gif. It can not determine that by itself. If you don't send the header the browser will try to interpret you gif image as HTML code, which usually gives, well, fascinating results :) > // 7x1 pixel GIF image data > $img = array ( > 0x47, 0x49, 0x46, 0x38, 0x37, 0x61, 0x07, 0x00, 0x01, 0x00, 0xF7, > 0x00, 0x00, 0x00, 0x00, 0x00, > 0x80, 0x00, 0x00, 0x00, 0x80, 0x00, 0x80, 0x80, 0x00, 0x00, 0x00, > 0x80, 0x80, 0x00, 0x80, 0x00, [...] > ) ; > // Write content type to browser > echo "Content-Type: image/gif\n\n"; > > // Write GIF image data to browser > foreach ($img as $val){ > echo $val; > } Try echo pack ('c*', $img); Or if that doesn't work: foreach ($img as $val) { echo pack ('c', $val); } -- Christian Reiniger LGDC Webmaster (http://sunsite.dk/lgdc/) ..10001000110101011010101101011110111010113...????