RE: Function to compare an array with another array

function ArrayCompare($array1, $array2) { $answer = new Array() foreach ($array1 as $element) { if (($key = array_search($element, $array2)) === false) { $answer[$key] = $array2[$key]; } } return $answer; } this will return an array that is a copy of the first array with only those elements that are not in array2. If you only want the first one either just use the first one( foreach(){ ... break;}) or put a break in the if. Tim Ward Senior Systems Engineer Please refer to the following disclaimer in respect of this message: http://www.stivesdirect.com/e-mail-disclaimer.html > -----Original Message----- > From: Jimmy Bäckström [mailto:broder_b@chello.se] > Sent: 05 March 2001 06:38 > To: PHP General List > Subject: Function to compare an array with another array > > > Shu! > I need some help here. > I have a script where I want to compare two arrays with > eachother, and return one value from that does not exists in > both arrays. I have an array of pictures id number created > from a database query. I use sessions to save id numbers of > pictures into an array. I want the first array to be compared > to the second and return the first key/value-pair that are > not found in the session array... > Is there a way I can do this? > > Thankful for any help! > /Broder B >