Re: Passing Array to Function ?

In article <3958595B.A3D27234@innovativeinternet.com>, jack@innovativeinternet.com (Jack Sasportas) wrote: > I am having problems passing an array to a function. > I could not find anything on the FAQ's or function info,although what I > did find made it seem that you could pass an array to a function. > I get parese errors.... function foo($array){ //This function assumes you pass in an array. while (list($k, $v) = each($array)){ echo "$k ==&gt; $v<BR>\n"; } } $bar = array('a' => 'apple', 'b' => 'banana', 'c' => 'coconut'); foo($bar); You're probably trying to indicate that the array is an array somehow in the function header. Don't. PHP is value-typed, not variable-typed: An array knows it's an array because it is an array, not because some function header or variable declaration told it it was. -- Richard Lynch | If this was worth $$$ to you, buy a CD US Customer Support Director | from one of the artists listed here: Zend Technologies USA | http://www.L-I-E.com/artists.htm http://www.zend.com | (this has nothing to do with Zend, duh!)