Re: fopen to validate a URL

Well I changed the code to this expecting a true or false response (1 or 0) $url=$row[url]; echo "Old URL = ".$url."<br>"; $fp = fopen("$url","r"); echo "fp = ".$fp."<br>"; //Debug line to see what $fp is returning switch ($fp){ case 1: echo "Valid URL<br>"; break; case 0: echo "URL IS NOT VALID<br>"; $url="http://"; break; } echo "New URL = ".$url."<br>"; I get this as a responce on a URL I know is valid (I tested it in my browser) Old URL = http://www.warrenbowley.com Warning: fopen("http://www.warrenbowley.com","r") - Bad file descriptor in /var/www2/html/members/datacopy.php on line 73 fp = URL IS NOT VALID New URL = http:// Kenneth R Zink II Hellcat1@S-Series.Org ICQ# 5095094 '87 2.8L TBI GMC S-15 Ext. Cab (Hurricane) ...524 in the works !!! http://www.s-series.org/htm/windstorm/project-windstorm.htm '85 3.4L Carbed Chevy S-10 Blazer (FireStorm) ...Soon to be 3.4L SFI DIS !!! http://www.s-series.org/htm/firestorm/firestorm.htm Racing by the Grace of God!! > on 3/15/01 04:39 PM, Hellcat1@EV1.Net splat open and thusly melted: > > > $url=$row[url]; > > > > echo "Old URL = ".$url."<br>"; > > > > $fp = @fopen($url,"r"); > > if ($fp){ > > echo "Valid URL<br>"; > > }else{ > > echo "URL IS NOT VALID"; > > $url="http://"; > > } > > > > echo "New URL = ".$url."<br>"; > > what exactly do you expect to happen, and what actually happens? i have a > feeling, based on your code, that your $url is missing the > "http://" part, > and the script is failing because of that.