Re: creating array on variable variable (bug?)

Thanks a million man! This did the trick... Best Regards, // Tobias Talltorp ""Mahmoud Abu-Wardeh"" <mahmoud@infoscience.ltd.uk> wrote in message news:IBEPJFAKLHILHMLAJGKDAEFPCDAA.mahmoud@infoscience.ltd.uk... > try this: (you need to escape the variable part of the variable variable > with {}) > > <?php > $name = "talltorp"; > > $$name = array(1,2,3,4); // <-- this works > > for ($i=0; $i<10; $i++) { // > ${$name}[] = $i; // <-- this will work now > } // > > for ($i=0; $i<sizeof($talltorp); $i++){ > > echo $talltorp[$i]; > } > ?> > > -----Original Message----- > From: Tobias Talltorp [mailto:tobias@talltorp.com] > Sent: 16 March 2001 00:15 > To: php-general@lists.php.net > Subject: [PHP] creating array on variable variable (bug?) > > > Hello all. > > Howcome I can create an array on a variable variable using array(), but not > in a for-loop (See code below)? > > <? > $name = "talltorp"; > > $$name = array(1,2,3,4); // <-- this works > > for ($i=0; $i<10; $i++) { // > $$name[] = $i; // <-- this does not work > } // > > for ($i=0; $i<sizeof($talltorp); $i++) > > echo $talltorp[$i]; > } > ?> > > In the for-loop I get this error message: > Fatal error: Cannot use [] for reading in > E:\Inetpub\wwwroot\testscript\sessions\test4.php on line 6 > > Is this a bug or do I have the bugs in my head finally gotten to my thinking > area? > > Thanks, > // Tobias Talltorp > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >