Cant configure php4 from within shell script

OK - this one really is stumping me. I have a shell script that I'm running through bash on my linux server.... it includes: ./configure \ --with-apache=../apache_1.3.17 \ --with-gd \ --with-mysql \ --with-gdbm \ --with-mhash \ --enable-safe-mode \ --enable-magic-quotes \ --enable-apc \ --enable-ftp \ --enable-debug=no \ --enable-memory-limit=yes \ --enable-xml \ --enable-track-vars When I run it as part of the script, I get this: checking for working makeinfo... found Updated php_version.h checking whether to enable maintainer-specific portions of Makefiles... no checking host system type... Configuration name missing. Usage: ./config.sub CPU-MFR-OPSYS or ./config.sub ALIAS where ALIAS is a recognized configuration type. checking for gawk... gawk checking for bison... bison -y checking bison version... 1.25 (ok) checking for gcc... gcc checking whether the C compiler (gcc ) works... yes but when I run the same (cut and pasted from the shell script) ./configuration... command I get: checking for working makeinfo... found Updated php_version.h checking whether to enable maintainer-specific portions of Makefiles... no checking host system type... i686-pc-linux-gnu checking for gawk... gawk checking for bison... bison -y checking bison version... 1.25 (ok) checking for gcc... gcc checking whether the C compiler (gcc ) works... yes What gives? System is Linux 5.2 (Linux version 2.0.36 ), bash version is GNU bash, version 1.14.7(1)