Re: Variables problem

I dont know how good of an idea it is to have 180 variable variable names. oi, headache. but the question you asked was this. " $q = 'tar1-1' how do I access the variable $tar1-1 " no problem echo $$q; -- Chris Lee lee@mediawaveonline.com ""Per Kallin"" <per@kallin.nu> wrote in message news:98va5j$3lp$1@toye.p.sourceforge.net... Hi! I have a quite big form to fill out a calendar. The form has six fields for every day in a month to make it possible to set up tree apointments (the target of the meeting and Locataion), this makes a total of about ~180 fields so I created them with a for-loop. Now I got this 180 fields named tar1-1, loc1-1, tar2-1, loc2-1 a.s.o. where the first tree letters tells what information it is, the 4th witch meeting it is (1-3) and the digits after the minus-sign tells the day of the month (1-31) The problem is to get the value out of the variable so i can store it in my mySQL database. it no problem to create a variable that holds the name of the variable that contains the data, but then??? The value of the variable $q is 'tar1-1' and I want to access the variable $tar1-1..... I can't find any way to solve this, can you? Someone most have created a calendar like this before... Please respond to per@kallin.nu /Per Kallin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net