Re: indirectly call function?

$module = "mod_news"; echo $module(); i think that's it. or: $module = "mod_news()"; eval("echo ".$module); I think the former is faster. -aaron At 7:16 PM -0500 3/24/01, Jaxon wrote:

hi all, I'm trying to change which function is called at runtime: e.g. page1.php: include "functions_def.inc.php"; //contains definition for mod_news() $module = "mod_news()"; //for example - gets assigned by case statement include page2.inc.php page2.inc.php: <?php echo $module; ?> the page shows "mod_news()" instead of calling my function :( It works if I use <?php echo mod_news(); ?> but not if I'm trying to hold the function name in the variable. I've tried <?php echo $module; ?> <?php eval $module; ?> <?php print $module; ?> all to no avail. any ideas? tks! jaxon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net