Re: PHP4 Output

I solved my own problem. PHP got the file name to run from the PATH_TRANSLATED environment variable. Changing that variable changes the file PHP will parse. Jordan ----- Original Message ----- From: "Jordan Pickup" <jordan@cynetech.com> To: <php-general@lists.php.net> Sent: Monday, July 03, 2000 1:45 PM Subject: [PHP] PHP4 Output > In PHP3 I could run a PHP program by specifying a filename as a parameter. I > realize that this feature is still there in PHP4 but I think the way it > works must have changed. It must also be able to get the file to run from > somewhere else. > > I call PHP directly from a different CGI script. With PHP3, I could make PHP > run on different files from within the original CGI Script. Now, no matter > what filename I specify as a parameter, PHP4 is going to run on the same > file that the original script was called on. > > So, my question is, how do I make this work in PHP4? What other way does the > PHP exe get the file it is parsing? Can I just change a environment variable > or is it more complicated than that? > > Example: > My original file is a Java program called on main.html. The java program > then calls PHP twice within itself to add a header and a footer that is > common to my other PHP files. The old output was main.html with the header > and footer added correctly. Now, the browser receives main.html with it > inserted into itself twice where the header/footer should have been. > > This is causing a major problem. I would appreciate any help on this > subject. > > jordan > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > >