Re: Caller's Line number?

Look at this example: 1: 2: write_debug_string("i'm here"); 3: 4: 5: write_debug_string("now i'm here"); 6: function write_debug_string($message) { echo sprintf("[DEBUG AT LINE %d] %s", get_callers_line(), $message); } this should output: [DEBUG AT LINE 2]: i'm here [DEBUG AT LINE 5]: now i'm here so basically, as if passing to the write_debug_string() a hidden parameter = __LINE__ but i don't want to pass it everytime. maybe in C language i could have written a macro that passes the __LINE__ for me. btw, any macros in PHP like in C? (#define xyz...) ""Yasuo Ohgaki"" <yohgaki@hotmail.com> wrote in message news:99sgbp$t8p$1@toye.p.sourceforge.net... > Not sure what you really mean. > > __LINE__ contains current line number in the script wherever it is used. So if > you want caller's line number > > function foo($line) { > echo 'Line number: '. $line; > } > > foo(__LINE__); > > You can get the caller's line number. (Line number of foo(__LINE__);) > > Regards, > -- > Yasuo Ohgaki > > > ""elias"" <elias_bachaalany@yahoo.com> wrote in message > news:99s17u$fd7$1@toye.p.sourceforge.net... > > Hello, > > > > can i make a function that displays the __LINE__ of it's caller? > > > > ie: > > > > function show_caller_s_line() > > { > > echo "my caller's line is:" . __LINE__; > > } > > > > 1: blahblahblah > > 2: show_caller_s_line() > > 3: blahblah > > > > output should be: > > my caller's line is: 3 > > > > > > is that possible? > > > > thanks. > > -elias > > > > > > > > -- > > PHP General Mailing List (http://www.php.net/) > > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > > For additional commands, e-mail: php-general-help@lists.php.net > > To contact the list administrators, e-mail: php-list-admin@lists.php.net > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >