Re: Catagory list

From: Date: Sat, 31 Mar 2001 01:27:07 +0000
Subject: Re: Catagory list
References: 1  Groups: php.general 
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please try this: - I didn't really get what you mean, but i can see that you have a table such: Table fields: category, fieldx, fieldy, fieldz, title and you want to display it's data as: category 1 title1 (belonging to cat1) title2 (...) title3 (....) title4 (...) cat2 titlex titley titlez that what you said, right? okay, try this: ** $result = mysql_query ("SELECT * from article ORDER BY catagory"); $temp = ""; while ($r = mysql_fetch_array($result)) { if (empty($temp)) // will be fired only once! { $temp = $r["category"]; // get category name echo "This is category $temp, and it's titles are as following:<br>"; // display it } if ($temp != $r["category"]) // because it's sorted by category, this method will work! echo "This is category $temp, and it's titles are as following:<br>"; // display it // update last category name $temp = $r["category"]; echo "----this is title " . $r["title"] . "<br>"; } ** - ""Mark Bayfield"" <mbayfield@optushome.com.au> wrote in message news:9a1u3q$k81$1@toye.p.sourceforge.net... > I am trying to make a catagory list that displays a distinct catagory, and > then listing titles under that catagory. > Unfortunatly all the data is in one table, and the catagory field is not set > catagories, so there is duplicates in that field. > The code so far is (but I am probably going about it the wrong way, if you > can see whats wrong with my code plase help, or point me in some direction), > > $query = mysql_query("SELECT DISTINCT catagory from article order by > catagory"); > $query2 = mysql_query ("SELECT * from article ORDER BY catagory"); > > for ($index = 0; $index < mysql_num_rows($query); $index++) { > $Catagory = mysql_fetch_row ($query) or die (mysql_error()); > $name1 = mysql_fetch_row ($query2) or die (mysql_error()); > $x = $name1; > $result1 = array_unique($Catagory); > $result = array_merge($Catagory, $name1); > > print ("$result1[0]<BR>"); > for ($x=0; $x == $result1[0]; $x++) { > print ("&nbsp;&nbsp;&nbsp;&nbsp;<a > href='update.php?passed=$name1[0]'>$name1[2]</a><br>\n"); > } > } > > I am trying everything to get it do just print the following: > > Catagory > title1 > title2 > Catagory1 > title3 > title4 > > Please help me out.... > > thanks > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >

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