RE: [PHP] PHP/MySQL Code

The comparison operator is ==. = means "assign". Try: if ($num == 0) { foo(bar, baz); } AFAIK what your code means is "assign 0 to $num and then, if that worked, print the error message." HTH Jon -----Original Message----- From: Jeff Oien [mailto:jeff@webdesigns1.com] Sent: 06 April 2001 17:51 To: PHP Subject: [PHP] PHP/MySQL Code This code won't work. I'm trying to get an error if the username is entered incorrectly but it won't go through the if brackets. I even tried printing out $num and it's 0. I also tried if ($num = "0") { if ($num = '0') { <?php include("connect.php"); $result=mysql_query("select * from table where username='$username'",$connection) or die ("Can't do it"); $num = mysql_numrows($result); if ($num = 0) { print "<html>error message etc. exit; } Jeff Oien -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net ********************************************************************** 'The information included in this Email is of a confidential nature and is intended only for the addressee. If you are not the intended addressee, any disclosure, copying or distribution by you is prohibited and may be unlawful. Disclosure to any party other than the addressee, whether inadvertent or otherwise is not intended to waive privilege or confidentiality' **********************************************************************