Re: putting a list of data into 3 columns?

Lindsay Adams <lindsay@dingos.net> wrote in message news:B6F4B5D1.46A0%lindsay@dingos.net... | Assuming your items are in an array | $items =array() //assume a bunch of items in this array | For($i = 0; $i< (count($items)/3); $i +=1){ | printf("%s\t%s\t%s",$items[$i],$items[$i+3],$items[$i+6]); | } | | Should print 3 columns of tab separated text. | Note: typed this quickly, untested, but the theory is sound. Might have to | twiddle the $i<(count... Section. | | If you have 8 itesm, as shown and you divide by 3 you get 2.xx | So, the the loop will print out: | | $items[0] $items[3] $items[6] | $items[1] $items[4] $items[7] | $items[2] $items[5] $items[8} | // because $items[8] doesn't exist, it won't print. | // if it spits out an error there, put a @in front of printf to turn off | error reporting. | | | On 4/7/01 11:58 AM, "Jack Dempsey" <dempsejn@georgetown.edu> wrote: | | > You don't need to count...in your loop you can do something like this: | > if($current_pos%3==0){ //then you're at a multiple of three | > //code to start new column here | > } | > | > -jack | > Neither of these were quite what I was looking for, I was hoping I could make a table with 3 <td>'s side by side, each having a third of the list of products (with <br> between them). Is this possible? If not I will try to adapt one of these methods. Cheers for your help, Donald