Re: assignment operator works for comparison??

> if($shiny = 0) This line is the same as if ((shiny = 0) == TRUE) It's common error with PHP and C. You could make use of this like if ($fp = fopen($filename,'r')) since this is the same as if (($fp = fopen($filename,'r')) == TRUE) code after this line is executed when fopen() success to open file. Regards, -- Yasuo Ohgaki ""Dan"" <iridium77@hotmail.com> wrote in message news:9avrti$olc$1@toye.p.sourceforge.net... > This confused me for awhile, because the single equal sign seemed to work > for comparison, but created inexplicable errors in my programs. It seems > strange to me that a successful variable value assignment does not return > true. > > example: > > <? > > $shiny = 1; > if($shiny = 0){ echo("This wont print"); } > echo( $shiny ); //this will return 0 > > ?> > > --Dan > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >