Re: return parse error

"or" requires expression. "return" is not a expression. That why you get parse error. Regards, -- Yasuo Ohgaki ""Peter Harkins"" <ph@malaprop.org> wrote in message news:75b9123bacd3da880b4f1694dce32cf0@news.php.net... > This generates a parse error: > mysql_connect("localhost", "root", "rootpw") or > return("bar"); > > But all the following work fine: > mysql_connect("localhost", "root", "rootpw") or > die("bar"); > > mysql_connect("localhost", "root", "rootpw") or > print("bar"); > > if (!mysql_connect("localhost", "root", "rootpw")) { > return("bar"); > } > > Why? mysql_connect returns false on failure either way... I notice die > > and print are functions but return seems not to be, it doesn't have a > 'function.[name].html' file in the manual. *scratches head* I can't see > > any reason in the manual for this behavior. Am I missing something? > > PHP is running on Linux 2.2.19 and identifies as '4.0.2'. phpinfo also > says: > './configure' '--with-mysql' '--with-apache=../apache_1.3.12' > '-- > enable-track-vars' '--disable-debug' '--disable-xml' > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >