Re: Wrong parameter count

Hi Peter, @ 11:40:06 PM on 4/16/2001, Peter Houchin wrote: > Hi, can some one please help me figure out why the value $device > isn't being passed on out of the select box? i keep getting this > message when i view the source (OK, lets try this again) > Wrong parameter count for mysql_result() in D:\erentals/1.php on line 19 > <form name="select" method="post" action="1.php"> > <select name="device"><? > $query ="SELECT DISTINCT device FROM 3backup"; > $result = mysql_query($query); > $device = mysql_result($rs); // line 19 Two parameters are required, the third is optional. mixed mysql_result (int result, int row [, mixed field]) So you're just getting one row with mysql_result(). You probably want mysql_fetch_array() or mysql_fetch_object() if you want more than one row. If you don't, you'll need to use mysql_result($rs,$i) where $i is a row number. -Brian -- PGP is spoken here: 0xE4D0C7C8 Please, DO NOT carbon copy me on list replies.