Re: Variable variable

"Plutarck" <aemuli@spamclause-yahoo.com> wrote: > Your problem has little to do with the things mentioned. > > First of all, you are refering to a variable variable incorrectly. Actually, he's not. >You must > use brackets, like this: > > ${$id} The braces aren't required in this case. Of the four examples below, only the 3rd won't return the expected results - because the first $ is interpreted as a literal $. Paste the code below into a webpage and see for yourself. <?php $field = 'name'; $name = 'Steve'; echo '<br>' . $$field; echo '<br>' . ${$field}; echo '<br>' . "My name is $$field."; echo '<br>' . "My name is ${$field}."; ?> I have a few possible explanations for the problem of the original poster (see below). > if (${$id} == "on") > { > echo 'on'; > } else > { > echo 'off'; > } 1. If $id is a number I believe PHP will choke b/c I don't believe numbers can be used as variable names. 2. Assume $id = 'age_bracket'. The control structure checks to see if $age_bracket == "on". To set $id in the first place for your multiple checkbox values, you'd have to loop through the values sent from the form. Jack (original poster), did you do that? If your form's method = post then you would loop through $HTTP_POST_VARS and if it was get $HTTP_GET_VARS (and then only loop through the checkbox variables). Or you could predefine the checkbox variables using: $checkbox_fields = array( 'age_bracket', 'weight', 'gender', 'occupation' ); And then loop through as follows: while( list( , $val ) = each( $checkbox_fields ) ) { // may have to set as $$GLOBALS[$val] if within a function or declare $val as global first. if ( $$val == 'on' ) { echo 'on'; } else { echo 'off'; } } -- Steve Werby President, Befriend Internet Services LLC http://www.befriend.com/