Re: Regular Expressions?

Ahh.... It makes more sense now. Thanks. Jason "Brian Clark" <brianj@fusionwerks.com> wrote in message news:190208283290.20010420031324@fusionwerks.com... > Hi Jason, > > @ 3:08:06 AM on 4/20/2001, Jason Caldwell wrote: > > > Sorry if I seem dense. Your answer (although probably right on target) > > leaves me still confused :-) > > No problem at all. > > > The example you gave me: > > > $string = 'aaaa.aaaa'; > > print(eregi("^([[:alnum:]]+\.[[:alnum:]]+)", $string) ? 'matched' : > > 'no > > match'); > > > Now with your example (above) the following MATCHED (when, I think it > > shouldn't have:) > > > (example 1) > > aaaa.a! > > Matches because there is *at least* one alnum after the \. > It doesn't care about the ! as long as it found the a. > > > aaaa.a#$% > > Ditto here. > > > aaaa.a23!% > > Ditto here. > > > The following did NOT match. > > > (example 2) > > a!.aaaa > > This didnt' match because of ^[[:alnum:]]+\. > > There's a [:punct:] between the [:alnum:] and the \. > > > a%!.aaaa > > Ditto here. > > > aaaa.!a34 > > No [:alnum:] after the \. > > Your expression asks for *at least one* [:alnum:] > > Changing + to * would make that match. > > > Now when I took your example and added the $ at the end, like so: > > > print(eregi("^([[:alnum:]]+\.[[:alnum:]]+)$", $string) ? 'matched' : > > 'no > > match'); > > > Everything that MATCHED in example 1 no longer matched, > > Right, because it had a [:punct:] before the end of the string and you > forced it to only pick up [:alnum:]'s > > -Brian > -- > PGP is spoken here: 0xE4D0C7C8 > Please, DO NOT carbon copy me on list replies. > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > For additional commands, e-mail: php-general-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >