Re: dir()

On 6 Jul, Comron E Sattari wrote: > hey, > > I'm trying to use dir() to get a listing of subdirectories... but i am > failing. > > here is the code, but it is only echo'ing files, no directories... > > > $i = 0; > $d = dir("./image.db"); > while($entry=$d->read()) > { > echo $entry . "<BR>"; > if ( is_dir($entry) ) > > $array[$i++] = $entry; } > } > $d->close(); > /*echo count($array); debug*/ > > for($i = 0; $i < count($array); $i++) > { > echo $array[$i]; > } > > > thanks, > comron You may need to prepend the directory name to $entry before you test if it is a directory, otherwise the test will be made in the current working directory, which may not be what you want. Cheers -- David Robley | WEBMASTER & Mail List Admin RESEARCH CENTRE FOR INJURY STUDIES | http://www.nisu.flinders.edu.au/ AusEinet | http://auseinet.flinders.edu.au/ Flinders University, ADELAIDE, SOUTH AUSTRALIA